之前看到 @疯疯爱 建议图包按分辨率分类一下，H图额外一个文件夹。
本来想回复写个py脚本分类挺方便的，但一想人家又不一定会，干脆自己来干了。别问H图识别，问就是不会。
不过python环境还是要自己手动搭的，python3.8.3环境，还需要shutil和Pillow扩展，我太懒啦不想打包
import os, sys, shutil
from PIL import Image
Image.MAX_IMAGE_PIXELS = None
def checkFolder(dir):
if not os.path.exists(dir):
os.makedirs(dir)
def obtainResolution(imagePath, args):
with Image.open(imagePath) as image:
args[0] = max(image.width, image.height)
args[1] = min(image.width, image.height)
if image.width == image.height:
args[2] = 0
else:
args[2] = 1 if image.width > image.height else -1
def compareResolution(args, resolution, obortOrientation):
lastResolution = "other"
for item in resolution:
temp = item.split('x')
if args[0] >= int(temp[0]) and args[1] >= int(temp[1]):
lastResolution = item
else:
break
if obortOrientation:
if args[2] == -1:
return os.path.join(lastResolution, "vertical")
elif args[2] == 1:
return os.path.join(lastResolution, "horizontal")
else:
return os.path.join(lastResolution, "square")
else:
return lastResolution
#图片类型
suffix=".jpg.png"
obortOrientation = False
#分辨率分组
resolution = ["1280x720","1366x768","1600x900","1920x1080","1920x1200","2560x1440","2560x1600","3840x2160","5120x2880","7680x4320"]
path = input("Input path:")
#0:长宽中的最大值
#1:长宽中的最小值
#2:0正方形，1横向矩形，-1纵向矩形
args = [0, 0, 0]
for fileName in os.listdir(path):
if os.path.isfile(os.path.join(path, fileName)):
portion = os.path.splitext(fileName)
if portion[1] in suffix:
obtainResolution(os.path.join(path, fileName), args)
resolutionPath = compareResolution(args, resolution, obortOrientation)
checkFolder(os.path.join(path, resolutionPath))
shutil.move(os.path.join(path, fileName),
os.path.join(path, resolutionPath, fileName))
很简陋但胜在能用，能做个大致的分辨率分类。不过这里还有个问题，如果是同套图中出现分辨率不一致的话，图可能会被分到多个不同的文件夹。
obortOrientation = True的话还能再建一层子目录来区分横图还是纵图
文文第74弹图包Part1的效果，不过分类这1300+的图花了六七秒
最后强烈建议学python，简单好用，日常可以写好多小工具